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X is KMnO₄ as well as K₂Cr₂O₇
Because, in highly acidic medium, both KMnO₄ and K₂Cr₂O₇ oxidise chloride ion into chlorine gas
The equations are:
10Cl⁻ + 2MnO₄⁻ +14H⁺ → 5Cl₂ + 2Mn²⁺ + 7H₂O
10NaCl + 2KMnO₄ + 7H₂SO₄ → 5Cl₂ + 2MnCl₂ + 2KCl + 7H₂O
6Cl⁻ + Cr₂O₇²⁻ + 14H⁺ → 2Cr³⁺ + 3Cl₂ + 7H₂O
6NaCl + K₂Cr₂O₇²⁻ + 7H₂SO₄ → Cr₂O₃ + 3Cl₂ + 2KCl + 7H₂O
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