Math, asked by aanyas477, 3 months ago

answer this question with explanation​

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Answered by tarracharan
0

\bold{ ⇒\dfrac{4 -  \sqrt{25 - a} }{a - 9}}

\bold{ = \dfrac{4 -  \sqrt{25 - a} }{a - 9} \times  \dfrac{4  +   \sqrt{25 - a} }{4  +   \sqrt{25 - a} } }

\bold{ =  \dfrac{16 - (25 - a)}{(a - 9)(4  +  \sqrt{25 - a} )} }

\bold{ =  \dfrac{ - 9  +  a}{(a - 9)(4  +  \sqrt{25 - a} )}  }

=\bold{\red{ \dfrac{ 1}{(4  +  \sqrt{25 - a} )}}}

Answered by FairyLight
4

Answer:

Refer to the attachment mate..

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