Math, asked by vaibhavaugust2006, 1 year ago

Answer this question with full explanation

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Answered by sarthukadlag
2

Answer:

yes they are

Step-by-step explanation:

p(-2)= 2(-2)^3 -3(-2)^2 -11(-2)+6

= -16-12+22+6

= -28+28

= 0

p(3)=2(3)^3 -3(3)^2 -11(3)+6

=54-27-33+6

=54+6-27-33

=60-60

=0

Thus proved that -2 and 3 are zeroes of the given polynomial

Answered by Prateek5015
0

Answer:

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Step-by-step explanation:

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