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Answered by
2
Answer:
yes they are
Step-by-step explanation:
p(-2)= 2(-2)^3 -3(-2)^2 -11(-2)+6
= -16-12+22+6
= -28+28
= 0
p(3)=2(3)^3 -3(3)^2 -11(3)+6
=54-27-33+6
=54+6-27-33
=60-60
=0
Thus proved that -2 and 3 are zeroes of the given polynomial
Answered by
0
Answer:
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Step-by-step explanation:
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