Math, asked by sky83, 1 year ago

answer this question with process​

Attachments:

Answers

Answered by arjunnani
1
Let x² be the largest six-digit perfect square. 

The largest six-digit number is 999,999, so 
x² ≤ 999,999. 

You know that 1,000² = 1,000,000, which is only 1 more than 999,999, so x² must be the next smaller square, which is (1,000 - 1)². 
(1,000 - 1)² = 999² = 998,001. 

sky83: what _
sky83: what ≤
arjunnani: didnt u understand
arjunnani: We know the greatest number of 6 digits is 999999.
 Then solving through division method,
We get quotient as 999.99 So it is not a perfect square.
But if we consider it to be as (1000-1)² which will be equal to 999².

             (1000 - 1)² = 999² = 998001
.·.The greatest 6 digit number which is a perfect square is 998001.        

Read more on Brainly.in - https://brainly.in/question/25832#readmore
Answered by Nitinmundhra
0

Answer:

998001 = (999)²

Step-by-step explanation:

1. Do the long division method of square root for highest six digit number

i.e 999999

2. Subtract the remainder from the number

999999 - 1998

=998001

This is our answer

(You can apply this for same kind of questions for finding greatest number only)

Attachments:
Similar questions