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Let x² be the largest six-digit perfect square.
The largest six-digit number is 999,999, so
x² ≤ 999,999.
You know that 1,000² = 1,000,000, which is only 1 more than 999,999, so x² must be the next smaller square, which is (1,000 - 1)².
(1,000 - 1)² = 999² = 998,001.
The largest six-digit number is 999,999, so
x² ≤ 999,999.
You know that 1,000² = 1,000,000, which is only 1 more than 999,999, so x² must be the next smaller square, which is (1,000 - 1)².
(1,000 - 1)² = 999² = 998,001.
sky83:
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Then solving through division method,
We get quotient as 999.99 So it is not a perfect square.
But if we consider it to be as (1000-1)² which will be equal to 999².
(1000 - 1)² = 999² = 998001
.·.The greatest 6 digit number which is a perfect square is 998001.
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Answer:
998001 = (999)²
Step-by-step explanation:
1. Do the long division method of square root for highest six digit number
i.e 999999
2. Subtract the remainder from the number
999999 - 1998
=998001
This is our answer
(You can apply this for same kind of questions for finding greatest number only)
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