Question

Answer this question with proper Steps
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Answer 1

Answer:

Explanation:

LET THE RESISTORS BE :

R₁= 10 OHMS.

R₂= 20 OHMS.

SINCE CONNECTED IN PARALLEL

R NET = R₁R₂/(R₁+R₂)

R NET = 10*20/(20+10)

R NET = 200/30

R NET = 20/3

R NET = 6.66 OHMS.

CURRENT FLOWING , I = 6 A

VOLTAGE , V = ?

ACCORDING TO OHMS LAW

V = IR

V = 6*6.66

V = 39.96=40 V

SINCE THEY ARE CONNECTED IN PARALLEL SAME VOLTAGE ACROSS THE RESISTORS.

40 = I₁10

I₁ = 4 A

40 = I₂20

I₂ = 2 A.

HENCE THE CURRENT ARE :

 I ₁ = 4 A

 I ₂ = 2 A

HOPE THIS HELPS.