Question

Answer this question with solution..​

Answer 1

In the magnetic meridian the vertical and horizontal components of the magnetic field are ; Bv = Bsinδ and Bh = Bcosδ.The projection of the horizontal component Bh onto the geographic meridian is Bg = Bhcosθ.

The plane perpendicular to the geographic meridian makes angle 180∘−(90∘+θ) = 90∘−θ with the magnetic meridian. The projection of Bh onto this plane is Bp = Bhcos(90∘−θ) = Bhsinθ.

The apparent angles of dip in the geographic meridian and the plane perpendicular to it are given by

tanδ1=Bv/Bg ;

tanδ2=Bh/Bp ;

Therefore :

tanδ1 / tanδ2 = Bp / Bg = (Bhsinθ) / (Bhcosθ) = tanθ

θ = tan−1 (tanδ1 / tanδ2)

HOPE THIS HELPS YOU ✌️✌️☘️☘️