Question

Answer this question with solution plzzz fasttr​

Answer 1

Answer:

The value of x = 32

Among the given option, Option a) 32 is the correct answer

Step-by-step explanation:

Given,

$\sf {log_5\:log_5\:log_2\:x \:=\: 0}$

Taking $log_5$ to RHS.

$\sf {\implies log_5\:log_2\:x \:=\: 5^{0}}$

$\sf {\implies log_5\:log_2\:x \:=\: 1}$

Taking $log_5$ to RHS.

$\sf {\implies log_2\:x \:=\: 5^{1}}$

$\sf {\implies log_2\:x \:=\: 5}$

Taking $log_2$ to RHS.

$\sf {\implies x \:=\: 2^{5}}$

$\sf {\implies x \:=\: 32}$

$<b><u>•°• The value of x = 32</u></b>$

Answer 2

Answer:-

5log now take RHS.

$\sf {\implies log_2\:x \:=\: 5^{1}}⟹log2$

$\sf {\implies log_2\:x \:=\: 5}⟹log 2$

2log now take RHS

$\sf {\implies x \:=\: 2^{5}}⟹x=2 </p><p>5$

$\sf {\implies x \:=\: 32}⟹x=32$