Question

answer this question with steps ​

Answer 1

★ Solution :-

As we know that, the shopkeeper cheats as 990 g for every 1 kg for every item. So, the total weight cheated by the shopkeeper will be,

$\sf \leadsto 1 \: kg - 990 \: gm$

$\sf \leadsto 1000 - 990$

$\sf \leadsto 10 \: grams$

We have found that, he cheats 10 grams for every 1 kg. So, the cheated weight for 5/2 kg of sugar will be,

$\sf \leadsto \dfrac{\dfrac{5}{2} \times 10}{1000}$

$\sf \leadsto \dfrac{5 \times 5}{1000}$

$\sf \leadsto \dfrac{25}{1000}$

$\sf \leadsto \dfrac{1}{40} \: kg$

So, now we'll find the fraction of weight cheated by the shopkeeper.

Fraction of amount cheated by shopkeeper :

$\sf \leadsto \dfrac{Cheated \: weight}{Total \: weight}$

$\sf \leadsto \dfrac{\dfrac{1}{40}}{\dfrac{5}{2}}$

$\sf \leadsto \dfrac{1}{40} \div \dfrac{5}{2}$

$\sf \leadsto \dfrac{1}{40} \times \dfrac{5}{2}$

$\sf \leadsto \cancel \dfrac{5}{80} = \dfrac{1}{16}$

Therefore, Neha was cheated by 1/16 of sugar.