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let the age of father=x years
daughter age=70-x years
after 10 years daughter age=x+10
father age=10+70-x=80-x
equation becomes
x+10=2 (80-x)
x+10=160-2x
x+2x=160-10
3x=150
x=150/3=50
daughter age=70-50=20 years
father age=50 years
Answered by
1
Let father's age=x
Daughter's age=y
According to statement,
x+y=70 -(1)
After 10 years,
x+10=2(y+10)
x+10=2y+20 -(2)
From (1),
x=70-y
Substitute this value of x in (2)
(70-y)+10=2y+20
70-y+10=2y+20
80-y=2y+20
-y-2y=20-80
-3y=-60
3y=60
y=60/3
[y=20] -(age of daughter)
Now, use value of y in (1)
x+20=70
x=70-20
[x=50]
Therefore, age of father (x)= 50 years
age of daughter (y)= 20 years
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