Question

Answer this questions​

Answer 1

Answer:

Empiricaz formula is CH

2

O

Mass of Empirical formula =12+12+16=30g

Vapour density =

2

Molar mass of compound

∴90=

2

Molar mass

Molar mass of compound =180g

On dividing the

Empirical formula mass

Molecular formula mass

n=

30

180

=6

On multiply each atom of empirical formula by n we get actual molecular formula

C×+H

2

×6+O×6=C

6

H

12

O

6

The molecular formula of compound is C

6

H

12

O

6

with molar mass 180.

Answer 2

Answer:

r = 12.5%

Step-by-step explanation:

A = P(1+rt)

18000 = 9000 (1 + 8r)

(1+8r) = 18000÷9000 = 2

8r = 2-1

r = 1/8

r = (1/8)×100

r = 12.5%