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Answer:
Empiricaz formula is CH
2
O
Mass of Empirical formula =12+12+16=30g
Vapour density =
2
Molar mass of compound
∴90=
2
Molar mass
Molar mass of compound =180g
On dividing the
Empirical formula mass
Molecular formula mass
n=
30
180
=6
On multiply each atom of empirical formula by n we get actual molecular formula
C×+H
2
×6+O×6=C
6
H
12
O
6
The molecular formula of compound is C
6
H
12
O
6
with molar mass 180.
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Answer:
r = 12.5%
Step-by-step explanation:
A = P(1+rt)
18000 = 9000 (1 + 8r)
(1+8r) = 18000÷9000 = 2
8r = 2-1
r = 1/8
r = (1/8)×100
r = 12.5%
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