Question

answer this questions

Answer 1

$x = \frac{5 - \sqrt{3} }{5 + \sqrt{3} } \times \frac{5 - \sqrt{3} }{5 - \sqrt{3} } \\ { \frac{(5 - \sqrt{3)} }{ {5}^{2} - { \sqrt{3} }^{2} } }^{2} \\ \frac{28 - 10 \sqrt{3} }{22} \\ y = \frac{5 + \sqrt{3} }{5 - \sqrt{3} } \times \frac{5 + \sqrt{3} }{5 + \sqrt{3} } \\ { \frac{(5 + \sqrt{3)} }{ {5}^{2} - { \sqrt{3} }^{2} } }^{2} \\ \frac{28 + 10 \sqrt{3} }{22} \\ {x}^{2} - {y}^{2} = \frac{28 - 10 \sqrt{3} }{22} - \frac{28 + 10 \sqrt{3} }{22} \\ \frac{ - 20 \sqrt{3} }{22} = \frac{ - 10 \sqrt{3} }{11}$

Answer 2

Answer:

\begin{lgathered}x = \frac{5 - \sqrt{3} }{5 + \sqrt{3} } \times \frac{5 - \sqrt{3} }{5 - \sqrt{3} } \\ { \frac{(5 - \sqrt{3)} }{ {5}^{2} - { \sqrt{3} }^{2} } }^{2} \\ \frac{28 - 10 \sqrt{3} }{22} \\ y = \frac{5 + \sqrt{3} }{5 - \sqrt{3} } \times \frac{5 + \sqrt{3} }{5 + \sqrt{3} } \\ { \frac{(5 + \sqrt{3)} }{ {5}^{2} - { \sqrt{3} }^{2} } }^{2} \\ \frac{28 + 10 \sqrt{3} }{22} \\ {x}^{2} - {y}^{2} = \frac{28 - 10 \sqrt{3} }{22} - \frac{28 + 10 \sqrt{3} }{22} \\ \frac{ - 20 \sqrt{3} }{22} = \frac{ - 10 \sqrt{3} }{11}\end{lgathered}

x=

5+

3

5−

3

×

5−

3

5−

3

5

2

−

3

2

(5−

3)

2

22

28−10

3

y=

5−

3

5+

3

×

5+

3

5+

3

5

2

−

3

2

(5+

3)

2

22

28+10

3

x

2

−y

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=

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28−10

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−

22

28+10

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−20

3

=

11

−10

3