Question

answer this questions for me friends ​

Answer 1

Solution + Explaination ..

13)(d) Energy density

It is defined as the energy per unit volume of The parallel plate capacitor.

A×d

So we can find energy density =

U = 1/2 CV ^2.

14.(b) 2

Given ,

2 uF and 2 uF are in series

So apply the formula for capacitance in series :

C1×C2 / C1+C2

and we get

4/4

1

Now ,

1uF and 1uF will be in parallel

And formula for capacitance in parallel is C1 + C2 so final answer will be

1+1 = 2

( kindly refer to the attachment for diagrammatic explanation).

15) a) 3× 10^-2

Given data ,

Q1 = -1 ×10^-2

Q2 = -5× 10^-2

Q1 + Q2 = equivalent

(adding both the quantities we get)

4×10^-2

The total charge .

As we know that V1 is equal to V2

therefore,

kQ1/r1 = kQ2/r2

now,

Q1/1 = Q2/3

1:3

Q1 = 1/4 ×4×10^-2

now the final obtained answer will be,

Q1 = 10^-2

and Q2 = 3×10^-2