Answer this questions to get the points.
Attachments:
Answers
Answered by
2
Answer:
Density of candle is half of the density of water. Therefore, it will always remain half in the water. Hence, if it burns 2 cm/h, the candle will come up by 1 cm from the water. Therefore, the top of the candle will fall at the rate of 1 cm/h.
Explanation:
Since half of the candle floats up when in initial equilibrium, density of the candle is half of density of water.
Thus it always remains half inside water and half outside. Thus after an hour, the length of candle would decrease by 2cm and half of it would remain in water and half outside. Thus the fall in the top of the candle would be 1cm.
Thus rate of fall of top of the candle is 1cm/h.
Answered by
1
Answer:
Answer:
Density of candle is half of the density of water. Therefore, it will always remain half in the water. Hence, if it burns 2 cm/h, the candle will come up by 1 cm from the water. Therefore, the top of the candle will fall at the rate of 1 cm/h.
Explanation:
Since half of the candle floats up when in initial equilibrium, density of the candle is half of density of water.
Thus it always remains half inside water and half outside. Thus after an hour, the length of candle would decrease by 2cm and half of it would remain in water and half outside. Thus the fall in the top of the candle would be 1cm.
Thus rate of fall of top of the candle is 1cm/h.
Please brainlest me the answer
Similar questions