Question

answer this questuon
figure and question is given ..

Answer 1

Answer:

1) ar of triangle PQX = 40 cm^2

ar of triangle QRX = 40 cm^2

2) length of AB = 1.68 cm

ar of triangle ABC = 5.04cm^2

Step-by-step explanation:

1) diagonal divide the rectangle in equal areas

two diagonals divide rectangle in 4 equal triangle

area of rectangle = l × b = 16 × 10 = 160 sqcm

area of 4 triangle = 160

ar of PQX = 160/4 = 40 sqcm

ar of QRX = 160/4 = 40 sqcm

2) area of triangle ABD = 1/2 × b × h

$8.4= \frac{1}{2} \times 10 \times h \\ h = \frac{8.4 \times 2}{10} \\ h = \frac{16.8}{10} \\ h = 1.68$

area of triangle ABC

$\frac{1}{2} \times b \times h \\ = \frac{1}{2} \times 6 \times 1.68 \\ = 3 \times 1.68 \\ = 5.04 {cm}^{2}$