Physics, asked by amandubey831, 5 months ago

Answer this quick please ​

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Answered by manissaha129
0

Answer:

Magnitude of the vector :----

 |A| =   \sqrt{ {1}^{2}  + {( - 2)}^{2} +   {1}^{2} }   \\ =  \sqrt{1 + 4 + 1}  = \boxed{\sqrt{6}  \: units}

Unit Vector :----

 \huge{\frac{1}{ \sqrt{6} } i -  \frac{2}{ \sqrt{6}}j +  \frac{1}{ \sqrt{6} } k}

Answered by jayanid78
0

Answer:

1/√6 i - 2/√6 j+ 1√6 k

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