Answer this Riddle with solution
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Given :-
2x + 2x + 2x = 30 -------- Equation (1)
y + y + 2x = 20 ----------- Equation (2)
2z + 2z + y = 13 ----------- Equation (3)
x + [y + 2z{ in His Hand } + 2x{shoes}] * z = ?
Solving Equation (1), we get,
→ 2x + 2x + 2x = 30
→ 6x = 30
Dividing both sides by 6,
→ x = 5 .
Putting This value in Equation (2) now, we get,
→ 2y + 2*5 = 20
→ 2y = 20 - 10
→ 2y = 10
Dividing both sides by 2 ,
→ y = 5.
Putting This value in Equation (3) now, we get,
→ 4z + 5 = 13
→ 4z = 13 - 5
→ 4z = 8
Dividing both sides by 4,
→ z = 2.
Now, we Have to Find :- x + (y + 2z +2x) * z = ?
Putting all Three value now, we get,
→ 5 + (5 + 2*2+2*5) * 2
→ 5 + (5+4+10)*2
→ 5 + 19*2
→ 43 (Ans).
AbhijithPrakash:
Awesome!
Answered by
0
Answer:
one shoe=10
one man=5
one cone=4
10+5x4=
=30
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