Question

Answer this

Rohan's mother gave him ₹ (3xy square+4) and his father gave him ₹ (5xy2+2).
Out of this total money he spent ₹ (10–3xy square
) on his birthday party.

How much money is left with him?

Answer 1

Answer:

Given, amount given to Rohan by his mother

=Rs. 3xy2 and amount given to Rohan by his father

=Rs. 5(xy2 + 2)

∴ Total amount Rohan have = [(3xy2)+(5xy2 + 10)]

= Rs. [3xy2 + 5xy2 + 10] = Rs. (8xy2 + 10) Total amount spent by Rohan

=Rs. (10 – 3xy2)

∴After spending, Rohan have left money

Answer 2

Answer:

${5xy}^{2}$

Step-by-step explanation:

Given that

Amount given to Rohan by his mother = Rs .

${3xy}^{2}$

Amount given to Rohan by his father =Rs.

$5( {xy}^{2} + 2)$

Total amount Rohan have = Rs.

${3xy}^{2} + 5( {xy}^{2} + 2)$

= Rs.

${8xy}^{2} + 10$

Total amount spent by Rohan =Rs.

$(10 - {3xy}^{2} )$

After spending Rohan have left money

= Rs.

$( {8xy}^{2} + 10) -$

Rs.

$(10 - {3xy}^{2} )$

= Rs.

$( {8xy}^{2} + {3xy}^{2} + 10 - 10)$

= Rs.

${5xy}^{2}$