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Question :- calculate the mass of iron in 10kg of iron ore in which it contains 80% of pure ferric oxide
Answer:- first of all we can write the given values
We want to calculate the mass
Here 10kg is the value of iron ore
Here 80% of it contains pure ferric oxide
In 10,kg ........80% of Fe2O3 means it is 8Kg
So,...here the number of moles of Fe2O3 is given as
8000g/160
That is equal to 50 moles
Then now for one mole of Fe2O3 there will be 112kg of iron
And for the 50,moles it will be
50 X 112 = 5600g
= 5.6 kg
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