Math, asked by Ghost02, 11 months ago

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$\frac {1}{\sqrt5+\sqrt2}$

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Answered by Anonymous

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ANSWER:

$\frac{1}{ \sqrt{5} + \sqrt{2} } = \frac{ \sqrt{5} - \sqrt{2} }{ \sqrt{5} - \sqrt{2} } = \frac{ \sqrt{5} - \sqrt{2} }{5 - 2} = \frac{ \sqrt{5} - \sqrt{2} }{3}$

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Answered by CharmingPrince

${\huge {\underline {\underline {\mathfrak {\green {Answer }}}}}}$

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${\bigstar {\underline {\bf {\pink {Given\:in\:the\:question:-}}}}}$

● $\displaystyle\frac {1}{\sqrt5+\sqrt2}$

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${\bigstar {\underline {\bf {\pink {Solution\:of\:the\:question:-}}}}}$

= $\displaystyle\frac {1}{\sqrt5+\sqrt2}$

= $\displaystyle\frac {1}{\sqrt5+\sqrt2}× \displaystyle\frac {\sqrt5-\sqrt2}{\sqrt5-\sqrt2}$

= $\displaystyle\frac {\sqrt5-\sqrt2}{({\sqrt5})^{2}+({\sqrt2})^{2}}$

= $\displaystyle\frac {\sqrt5-\sqrt2}{5-2}$

= $\displaystyle\frac {\sqrt {5}+\sqrt{2}}{3}$

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Answer this!

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$\frac {1}{\sqrt5+\sqrt2}$