answer this someone please please
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LHS = 1 + (Cot²A) / (1+CosecA)
= {1 +CosecA + Cot²A} / ( 1+ CosecA)
On multiplying Numerator & denominator by ( (1- CosecA)
= {( 1+CosecA +Cot²A) ( 1-CosecA)} / (1-Cosec²A)
= (1+CosecA+Cot²A-CosecA -Cosec²A -Cot²A.CosecA) / (1-Cosec²A)
Using fundamental trigonometric identity:
Cot²A+1 = Cosec²A , DENOMINATOR = 1-Cosec²A= -Cot²A
And NUMERATOR = 1+Cot²A-Cosec²A-Cot²A.CosecA
= Cosec²A-Cosec²A - Cot²A.CosecA
= -Cot²A.CosecA
Now, LHS = (-Cot²A.CosecA)/(-Cot²A)
= CosecA= RHS
[Hence Proved]
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