Question

Answer this... Sooooo hard ___​

Answer 1

Given :-

• 12th term of A.P = 25

• Common difference = 3

$\Large \underline{ \underline{ \bf \purple{To \: Find :-}}}$

17th term of the given A.P

$\Large \underline{ \underline{ \bf \purple{Solution :}}}$

$\begin{gathered}\begin{gathered}\longrightarrow \sf A_{12} = a + 11d \\ \\ \longrightarrow \sf 25 = a + 11 \times 3 \\ \\\longrightarrow \sf 25 = a + 33 \\ \\\longrightarrow \sf a = 25 - 33 \\ \\\longrightarrow\underline{\boxed{ \sf a = - 8}}\end{gathered}\end{gathered}$

Now , 17th term of the A.P

$\begin{gathered}\begin{gathered}\longrightarrow \sf A_{17} = a + 16d \\ \\\longrightarrow \sf A_{17} = - 8 + 16 \times 3 \\ \\\longrightarrow \sf A_{17} = - 8 + 48 \\ \\ \longrightarrow \underline{ \boxed{ \sf \orange{A_{17} =40}}}\end{gathered}\end{gathered}$

Answer 2

$\implies$$\tt{A_{12}=a+11d}$

$\implies$$\tt{25=a+11×3}$

$\implies$$\tt{25=a+33}$

$\implies$$\tt{a=25-33}$

$\implies$$\tt{a=-8}$

$\tt\red{Now,17th \: term \: of \: the \: A.P.}$

$\implies$$\tt{A_{17}=a+16d}$

$\implies$$\tt{A_{17}=-8+16×3}$

$\implies$$\tt{A_{17}=-8+48}$

$\implies$$\tt{A_{17}=40}$