Question

answer this step by step plz.​

Answer 1

Step-by-step explanation:

let k=2

2^(2-1)(2^(2)-1)

2^1(2^2-1)

2(4-1)

2(3)

6

let k=3

2^(3-1)(2^3-1)

2^2(2^3-1)

4(8-1)

4(7)

28

hence, for value 2, 3 of k the solution is 6, 28 respectively.