Question

answer this step by step with explaination plz i will mark correct answr as brainleist​

Answer 1

Answer:

HERE YOU GO!!

Solution:-

given by:-

The polynomials ax^3-3x^2+4 and 2x^3-5x+a when divided by (x–2) leave the remainders p and q respectively.

here , x = 2

》ax^3-3x^2+4

》8a -12+4 = p

》8a-8 =p

2x^3-5x+a

》2×8-10+a = q

》a+6 = q

accourding to question:-

》p – 2q = 4

》8a-8 - 2(a+6) = 4

》8a -8-2a-12 =4

》6a = 4+20

》a = 24/6

》(a = 4) ans

☆i hope its help☆

Mark as brainliest

Answer 2

a=4

Step-by-step explanation:

It is given that a polynomial ax

3

−3x

2

+4 when divided by (x−2) leaves the remainder p. Let us substitute x=2 in ax

3

−3x

2

+4 and equate it to p as follows:

a(2)

3

−3(2)

2

+4=p

⇒(a×8)−(3×4)+4=p

⇒8a−12+4=p

⇒8a−8=p....(1)

Similarly, given a polynomial 2x

3

−5x+a when divided by (x−2) leaves the remainder q. Let us substitute x=2 in 2x

3

−5x+a and equate it to q as follows:

2(2)

3

−(5×2)+a=q

⇒(2×8)−10+a=q

⇒16−10+a=q

⇒6+a=q....(2)

It is also given that p−2q=4, we, now substitute the values of p and q from equations 1 and 2 as shown below:

p−2q=4

⇒8a−8−2(6+a)=4

⇒8a−8−12−2a=4

⇒6a−20=4

⇒6a=4+20

⇒6a=24

⇒a= 6

24

⇒a=4

Hence, a=4.