Math, asked by Anonymous, 1 year ago

answer this !!!!!!!

thank you !

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Answered by pankaj12je
6
Hey there !!!!

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Initially number of boys=x 

Number of girls=y

Total strength=x+y

Initial % of boys = number of boys/total strength 

  x/x+y= 60/100

  x/x+y= 3/5----Equation 1

According to question :

6 boys were admitted into the class and 6 girls left the class

So,

Number of boys= x+6

Number of girls= y-6

Total strength = x+6+y-6= x+y

 % of boys = x+6/x+y = 75/100

 x+6/x+y = 3/4----Equation 2

Dividing equation 1 and 2

x/x+y/x+6/x+y = 3/5/3/4

x/x+6=4/5

5x=4x+24

x=24

Substituting x=24 in Equation 1

x/x+y=3/5

24/24+y=3/5

24*5=24*3+3y

120-72=3y

48=3y

y=16

So original number of boys=24 and girls =16

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Hope this helped you...........
Answered by mfazal
4
Hope you find this helpful
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