Math, asked by manish5365, 10 months ago

answer this trigonometric problem please.

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Answered by Anonymous
2

Answer:

x = ( a + b ) / ( 1 - ab )

Step-by-step explanation:

Let A = arctan a.  Then...

a = tan A  =>  1 + a² = sec² A

=>  cos² A = 1 / ( 1 + a² )

and  sin² A = 1 - cos² A = a² / ( 1 + a² ).

So...

sin² 2A = ( 2 sin A cos A )² = 4 sin²A cos²A = 4a² / ( 1 + a² )²

=> sin 2A = 2a / ( 1 + a² )

=> 2A = arcsin [ 2a / ( 1 + a² ) ]

Similarly, letting B = arctan b, we get 2B = arcsin [ 2b / ( 1 + b² ) ].

Therefore the equation becomes:

2A + 2B = 2 arctan x

=> arctan x = A + B

=> x = tan ( A + B )

      = ( tan A + tan B ) / ( 1 - tan A tan B )

=> x = ( a + b ) / ( 1 - ab )

[ N.B. Actually, we haven't been careful about details like the signs of a and b here, so more work is needed really to ensure that this is spot on! But for elementary purposes, this should be adequate. ]


Anonymous: eh? Is that gratitude? I'm happy to help out, but this response seems potentially hurtful.
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