Question

Answer this with all steps

Answer 1

Answer:

(i) 5/12 ; (ii) 0.018

Step-by-step explanation:

In both cases apply a^3 + b^3 + c^3 = 3abc {if a+b+c=0}

(i) Let a=1/2

b=1/3

c=-5/6

a+b+c=>1/2+1/3+(-5/6)=>0

Therefore, (1/2)^3+(1/3)^3+(-5/6)^3=> 3(1/2)(1/3)(-5/6)

=5/12

(ii)Let a=0.2

b= -(0.3)

c=0.1

a+b+c=>0.2+(-0.3)+0.1=>0

Therefore, (0.1)^3+(-0.3)^3+(0.2)^3=> 3(0.1)(-0.3)(0.2)

=0.018

Hope it helps you:)

Answer 2

Answer:

Inbox kroge plzz.

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