Question

answer this with explanation
$\sec ^{2} (60) \: - \tan^{2} (60) \div \sin ^{2} (30) + \cos ^{2} (30)$​

Answer 1

Answer:

1

Step-by-step explanation:

sec²x - tan²x = 1

sin²x + cos²x = 1

=>( sec²60 - tan² 60 ) ÷ (sin²30 + cos²30)

=> 1/1 = 1

Answer 2

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