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we know the identity (a-b)(a+b) = a²-b²
By using this ,
= (x-y)(x+y) + (y-z)(y+z) + (z-x)(z+x)
= (x²-y²) + (y²-z²) + (z²-x²)
= x²-y²+y²-z²+z²-x²
= 0
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hope it will help you !!!!!
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