Math, asked by rizakkalra, 1 year ago

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Answered by harshal9860293159
0

Angle ACD=70

Angle AED=110

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Answered by HashtagNoName
0

Answer:

(i) 70° (ACD = ECD)

(ii)110°

Explanation:

In triangle ABC, angle A + angle B + angle C = 180°

25° + 45° + C = 180°

C = 180° - 70° = 110°

angle ACB + angle ECD = 180°(linear pair)

110° + ECD = 180°

ECD = 180° - 110° = 70°

In triangle ECD, angle AED = ECD + EDC ( Exterior angle property )

AED = 70° + 40° = 110°

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