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Step-by-step explanation:
In first question there is a mistake. It should be triangle ABD and triangle ACD.
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here we have given that ABC is an isosceles triangle
AB = AC
AD perpendicular to BC
- prove that triangle ABC congruent to triangle ACD
solution __ in triangle ABD and triangle ACD
AB = AC (given)
angel ADB = angle ADC (each of 90 degree)
BD = DC (perpendicular bisector the side into two equal parts)
hence it is proved that triangle ABD is congruent to triangle ACD bye SAS rule
2. (b) is<B= <C
by by cpct we can say that<B = <C
3. is d is the midpoint of AB
yes d is the midpoint of ab because perpendicular always bisects the side into two equal half
so we can say that BD is equal to CD
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