Question

answer thus question​

Answer 1

Answer:

x = 0

Step-by-step explanation:

${ (\frac{ - 3}{2}) }^{6} \times { (\frac{4}{9} )}^{3} = {( \frac{1}{2} )}^{3x} \\ \frac{ { (- 3)}^{6} }{ {2}^{6} } \times \frac{ ({ {2}^{2} )}^{3} }{ { ({3}^{2}) }^{3} } = \frac{1}{ {2}^{3x} } \\ \frac{729}{64} \times \frac{64}{729} = \frac{1}{ {2}^{3x} } \\ 1 = \frac{1}{ {2}^{3x} } \\ {2}^{3x} = 1 \: \: \: \: \: ( {2}^{0} = 1) \\ {2}^{3x} = {2}^{0} \\ base \: are \: equal \: hence \: power \: to \: be \: equal \\ 3x = 0 \\ x = \frac{0}{3} \\ x = 0$

hope you get your answer