Math, asked by BKGGSS, 1 year ago

answer to get 100 points

what's the remainder when

24 ^ 1947 is congruent to x (mod 17)

I need full explanation

if I get it I will mark u as brainlliest

please don't cheat

Answers

Answered by Anonymous
5

24 = 7 ( mod 17 ) 24² = 15 ( mod 17 )
24³ = 3 ( mod 17 ) 24⁴ = 4 ( mod 17 )
24³+² = 11 ( mod 17) 24 ki power 10 = 2 ( mod 17)
1947 = 16*121+11
24 ki power 16*121 = 1 ( mod 17 )
24¹¹ = 14 ( mod 17 )
Remainder :- 14

Hope it helps you.

Answered by Anonymous
0

HEY MATE

HERE IS YoUR ANSWEE

24       =   [ 7 ( mod 17 ) 24² = 15 ( mod 17 ) ]

24³     = [3 ( mod 17 ) 24⁴ = 4 ( mod 17 ) ]

24³+ ² = 11 ( mod 17) 24 .....................[ power 10 = 2 ( mod 17) ]

1947    = [16*121+11 ]

24 .........................[ power 16*121 = [1 ( mod 17 ) ]

24¹¹ = [14 ( mod 17 )  ]

HENCE ,REMAINDER  IS   [ 14  ]

#BE BRAINlY


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