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Let, the two numbers are a and b.
Given, LCM (a, b) = 380
This implies, 380 is divisible by both a and b……………………………….(i).
Given, HCF (a, b) = 18
This implies, both a and b are divisible by 18………………………………..(ii).
Combining (i) and (ii), we can say; 380 is divisible by 18……………………(iii).
But, in actuality, 380 is not divisible by 18.
So, the statement that ‘two numbers have 18 as their HCF and 380 as their LCM’ is wrong.
Given, LCM (a, b) = 380
This implies, 380 is divisible by both a and b……………………………….(i).
Given, HCF (a, b) = 18
This implies, both a and b are divisible by 18………………………………..(ii).
Combining (i) and (ii), we can say; 380 is divisible by 18……………………(iii).
But, in actuality, 380 is not divisible by 18.
So, the statement that ‘two numbers have 18 as their HCF and 380 as their LCM’ is wrong.
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Step-by-step explanation:
No, two numbers can't have 18 as their HCF and 380 as LCM because HCF of the numbers must be a factor of the LCM. Since 18 is not a factor of 380, it is not possible.
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