Question

Answer to my question. Please ​

Answer 1

Answer:

give the full question. I will answer.....

Answer 2

Step-by-step explanation:

Given that:-

a is a positive real number and a≠1 then

2sin theta

If theta =0°

then 2sin(0°)=2×0=0

If theta =30° then

2sin30°=2×1/2=1

If theta =45° then

2sin45°=2×1/√2=2/√2=√2

If theta =60° then

2sin60°=2×√3/2=√3

If theta =90° then

2Sin90°=2×1=2

So 2sin theta lies between 0° and 2

0≤2sin theta ≤2 if 0°≤theta ≤90°

except these above values are not possible