Math, asked by Anonymous, 6 months ago

Answer:

To solve our given problem we will use section formula :]

Section Formula states that, when a point divides a line segment internally in the ratio m:n, So the coordinates are :]

\tiny: \implies (x,y) =  \bigg \lgroup x =  \frac{m. {x}_{2} +n. {x}_{1} }{m + n} ,y=  \frac{m. {y}_{2} +n. {y}_{1} }{m + n} \bigg \rgroup \\  \\  \\

Let

(-1 , 7) = (x₁ , y₁)

(4 , -3) = (x₂ , y₂)

m = 2

n = 3

Upon Substituting coordinates of our given points in section Formula we get :]

\tiny: \implies (x,y) =  \bigg \lgroup x =  \frac{2 \times 4 +3 \times  - 1 }{2 + 3} ,y=  \frac{2 \times  - 3 +3 \times 7}{2 + 3} \bigg \rgroup \\  \\  \\

\tiny: \implies (x,y) =  \bigg \lgroup x =  \frac{8  - 3 }{2 + 3} ,y=  \frac{ - 6 +21}{2 + 3} \bigg \rgroup \\  \\  \\

\tiny: \implies (x,y) =  \bigg \lgroup x =  \frac{5 }{5} ,y=  \frac{15}{5} \bigg \rgroup \\  \\  \\

\tiny: \implies (x,y) =  \bigg \lgroup x =  1,y=  3 \bigg \rgroup \\  \\  \\

Answers

Answered by nishu1298
1

Answer:

teko fõllõw karne mai koi interest nahi....

fõllõw mê ❤️❤️

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