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★ Question :
In the given figure , if AD = 7√3 m
then find the value of BC.
★ Answer :
Given : AD = 7√3 m
Let BD = x and DC = y
In ΔABD
Tan30° = AD/BD
BD = AD cot 30°
x = 7√3× √3
x = 21 m
now, In ΔADC
Tan60° = AD/DC
DC = AD /tan60°
DC = AD cot 60°
DC = 7 m
y = 7 m
BC = BD +DC
BC = x+y
BC = (21+7) m
BC = 28 m
I hope it helps you!
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