Question

Answer to the following

Answer 1

Step-by-step explanation:

$x ^{2} - \sqrt{3} x - 6 = 0 \\ x ^{2} - 2 \sqrt{3}x + \sqrt{3} x - 6 = 0 \\ x(x - 2 \sqrt{3} ) + \sqrt{3} (x - 2 \sqrt{3} ) = 0 \\( x + \sqrt{3} )( x- 2 \sqrt{3} ) = 0 \\ x = - \sqrt{3} \\ x = 2 \sqrt{3}$

$(a + 2b) {x}^{2} + 101x ( a + 2b) + 100 = 0 \\( a + 2b)x ^{2} + (a + 2b)x +( a + 2b)100x + 100 =0 \\ (a + 2b)x(x + 1) + (a + 2b)100(x + 1) = 0 \\(a + 2b)( x + 1)(x + 100) = 0 \\ x = - 1 \\ x = - 100$