Question

Answer to the question in the pic

Answer 1

We know 8=2³ and 8ˣ=$2^{3x}$
So,it is given 3x-y=12
and 8ˣ/2y =$2^{3x} /2^y= 2^{3x-y}$
From given 3x-y=12
So, The answer is $2^{12}$

Answer 2

Given
3x-y=12

Putting x=5, y=3

3(5)-3=12

15-3=12
12=12

LHS=RHS

Now putting

X=5, y=3

In 8^x/2^y,we get
$= \frac{ {8}^{5} }{ {2}^{3} }$


$= \frac{ {2 ^{3} }^{5} }{ {2}^{3} }$

$= \frac{ {2}^{15} }{ {2}^{3} }$
$= {2}^{12}$

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