Question

answer to this........​

Answer 1

Answer:

sorry for half answer

I don't know the answer of ii)

please forgive me...

Answer 2

Solutions:-

(ii)4x²+4√3x+3=0

Given,

4x²+4√3x+3=0

The standard quadratic equation is ax²+bx+c=0

D=b²-4ac

⇒48-4(4)(3)=0

Therefore, the roots exist are real and equal

Equation can be rewritten as

4x²+2√3x+2√3x+3=0

2x(2x+√3)+√3(2x+√3)=0

(2x+√3)²=0

⇒x = -√3/2

(iii)5x²-7x-6=0

The equation is

5x²-7x-6=0

⇒5x²+3x-10x-6=0

⇒x(5x+3)-2(5x+3)=0

⇒(x-2)(5x+3)=0

⇒x=2,-3/5