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x=10^3×0.0099 y=10^(-2)×110
x=10^3×99×10^(-4) y=10^(-2)×11×10
x=99×10^(-1) y=11×10^ (-1)
therefore x/y=(99×10^(-1))/(11×10^(-1))
=99/11
=9
so square root over x/y=3
x=10^3×99×10^(-4) y=10^(-2)×11×10
x=99×10^(-1) y=11×10^ (-1)
therefore x/y=(99×10^(-1))/(11×10^(-1))
=99/11
=9
so square root over x/y=3
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