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Answer -1
integer factors of 6 which are +-1,+-2,+-3,+-6
it is observed that........
f(-1) =(-1)^3+6(-1)^2+11(-1)+6 =-1+6-11+6 = 0
f(-2)= (-2)^3+6(-2)^2+11(-2)+6 = -8+24-22+6 = 0
f(-3) = (-3)^3+6(-3)^2+11(-3)+6= -27 +54 -33+6 = 0
Hence integer root of f(x) is -1 , -2 ,-3.....
✨Hope it will helps you.....!✨
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