Question

answer urgent please ​

Answer 1

Answer:

-2 is the answer of your ques tion

....

Answer 2

Step-by-step explanation:

let roots of both equations be p,q

sum of roots of ax^2+bx+c = -b/a

of first equation p+q = -(-3)/2 = 3/2

of second equation p+q = -(-6)/a =6/a

3/2 = 6/a

a= 6 ÷3/2 =6×2/3 =4

a=4

product of roots of ax^2+bx+c = c/a

lambda = k, mu = m

of first equation pq = k/2

of second equation pq = m/a = m/4

k/2 = m/4

k/m = 2/4 = 1/2

ka/m = k/m * a = 1/2 × 4 = 2

ka/m =2