answer will be
169 upon 229
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hope it helps you.....
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Anonymous:
I m sry the full pic is not coming
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PBP
--------- , sinA= P/H, cosA= B/H AND
HHB
tanA = P/B
cosA = 5/13 = B/H
it means
B=5, H= 13
by using pythagorous theorm
H²=P²+B²
P²= 13² - 5²
P² = 12²
P= 12
cosec A = 1/sinA
= H/P = 13/12
now,
cosecA/(cosA+cosecA)
= (13/12)/(5/13 + 13/12)
= (13/12)/ (60+169)/156
=
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