Question

answer with correct explanation is required please help ​

Answer 1

Answer:

solution

data given

moles of ammonia=4mol

first we have to relate second eqn

3H2 + N2 ----- 2NH3

let's compare

3H2----------2NH3

3mole of H2------------2mole of 2NH3

? ---------4mole of 2NH3

4mole of 2NH3 * 3mole of H2

----------------------------------------

2mole of 2NH3

6mole of H2 (then we have to compare again from eqn 1)

Zn + 2HCL-------ZnCl2 + H2

compare Zn and H2

1mole of Zn---------1mole of H2

? ---------6mole of H2

6mole of H2 * 1mole of Zn

----------------------------------------

1mole of H2

6mole of Zn

but

number of mole= mass/molar mass

then mass=number of mole * molar mass

6mole of Zn * 65 g/mol

390g

answer: 390g