Question

answer with explanation​

Answer 1

Answer:

40°

<CPA=<DPB_______(vertically opp. angle)

<CPA=120°

In∆CPA

40+120+CAP=180___(angle sum prop.)

160+CAP=180

CAP=20°

CAD=ADB

ADB=20°

In ∆BPD

120+20+CBD=180___(angle sum prop.)

140+CBD=180

CBD=40°