Math, asked by MansiGarg1111, 1 year ago

Answer with explanation.

Attachments:

RehanAhmadXLX: the pic is not losing
RehanAhmadXLX: loading
MansiGarg1111: :joy:

Answers

Answered by prmkulk1978
1
Given :ABCD is a rectangleED=16cmFG=FC=8cmBF=20cmFG is pependicular to BCCD=1/2 AD
To find : Area of shaded region
Solution :BC=BF+FC
=20+8
=28cm

CD=1/2 AD=1/2BC= 1/2 x 28=14m

AE=AD-ED =28-16=12cm
AREA OF SHADED REGION =AREA OF RECTANGLE - (AREA OF ΔAEB + AREA OF TRAPEZIUM)

=28X14 -(1/2 X12X14+1/2 X(8(8+14)

=392-(84+88)

=392-172

=220cm²

∴Area of shaded region is 220cm²


MansiGarg1111: Thanks ma'am ^_^
prmkulk1978: welcome
Similar questions