Physics, asked by Imnidhii, 10 months ago

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Answered by Atαrαh
2

d = 9× 10^3 kg /m³

M = 63 g = 0.063 kg

I = 1.1 A

d = 1 mm

r =1mm/2 = 0.5 mm

no of copper atomsper unit volume

n = N / V

d = M /V

V = d / M

n = d N / M

n = 9× 10^3 × 6.023 ×10^ 23 / 0.063

n =860 ×10^26

As one copper atom gives 1 free electron the total no of electrons become 8× 10^ 26

A = π r ²= 3.14 × 0.25 × 10 ^-6 =0.785 ×10^ -6

I = n e A V

V = I / n e A

V = 1.1 / 860 ×10^ 26 × 1.6 × 10^ - 19 × 0.785 × 10^-6

V = 1.1 /1080.16 ×10

V =1.1 /10800

V = 0.0001 m/s

V =0.1 mm/s

Answered by Nidhi0000
1

Explanation:

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