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d = 9× 10^3 kg /m³
M = 63 g = 0.063 kg
I = 1.1 A
d = 1 mm
r =1mm/2 = 0.5 mm
no of copper atomsper unit volume
n = N / V
d = M /V
V = d / M
n = d N / M
n = 9× 10^3 × 6.023 ×10^ 23 / 0.063
n =860 ×10^26
As one copper atom gives 1 free electron the total no of electrons become 8× 10^ 26
A = π r ²= 3.14 × 0.25 × 10 ^-6 =0.785 ×10^ -6
I = n e A V
V = I / n e A
V = 1.1 / 860 ×10^ 26 × 1.6 × 10^ - 19 × 0.785 × 10^-6
V = 1.1 /1080.16 ×10
V =1.1 /10800
V = 0.0001 m/s
V =0.1 mm/s
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