Math, asked by iamsree49, 7 months ago

Answer with explanation please...​

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Answered by udaybhan2017chauhan
1

Answer:

p(x) =  {x}^{3}  -  \sqrt{3}  {x}^{2}  + 2x - 5 \\  \\ p( \sqrt[3]{3} ) =  {( \sqrt[3]{3} )}^{3}-\sqrt{3}   \times {( \sqrt[3]{3} )}^{2}+ 2 \times  \sqrt[3]{3}  - 5 \\  \\  \:  \:  \:  \:  = { \sqrt[3]{3} }\times  { \sqrt[3]{3} }\times{ \sqrt[3]{3} }- \sqrt{3} ×{ \sqrt[3]{3} }×{ \sqrt[3]{3} }+{ \sqrt[6]{3} }-5\\\\ \:  \:  \:  \: ={ \sqrt[71]{3} }-{ \sqrt[27]{3} }+{ \sqrt[6]{3} }-5\\\\ \:  \:  \:  \:={ \sqrt[77]{3} }-{ \sqrt[27]{3} }-5\\\\ \:  \:  \:  \:={ \sqrt[50]{3} }-5

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