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Given AP : 24, 23 1/4, 22 1/2, 21 3/4,..........3
From the AP we get
a = 24 (first term)
d = 23 1/4 - 24 = - 3/4 (d = a₂ - a₁)
It is also given that,
aₓ = 3
We need to find x - the term that gives 3 in this AP
So, By using formula
aₓ = a + (x-1)d
3 = 24 + (x-1)(- 3/4)
3 - 24 = (x-1)(-3/4)
x - 1 = -21 ÷ (-3/4)
x - 1 = -21/-3 × 4
x - 1 = 7 × 4
x = 28 + 1
x = 29th term.
So, required term = 29
From the AP we get
a = 24 (first term)
d = 23 1/4 - 24 = - 3/4 (d = a₂ - a₁)
It is also given that,
aₓ = 3
We need to find x - the term that gives 3 in this AP
So, By using formula
aₓ = a + (x-1)d
3 = 24 + (x-1)(- 3/4)
3 - 24 = (x-1)(-3/4)
x - 1 = -21 ÷ (-3/4)
x - 1 = -21/-3 × 4
x - 1 = 7 × 4
x = 28 + 1
x = 29th term.
So, required term = 29
☺ Hope this Helps ☺
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