Question

Answer With Full Explanation ..​

Answer 1

Explanation:

given :

• rear side of truck = 40 kg mass

• cofficient of friction between box and surface

• = 0.15

• accelerates = 2ms -2

to find :

• fall off the truck, ignore the size of the box = ?

• fall off the truck, ignore the size of the box = ?

according to QUESTION:

• box mass = 40 kg

• u = 0.15

• accelerates = 2m/s 2

• speed = 5m

• force = ma

• force = 40×2=80

• truck acceleration

• force = μmg

• force = 0.15×40×10=60

• net force block

• force net = 80 - 60 = 20

acceleration backward :

• backward = force net / m = 20/40 = 0.5 m/s

equation of motion of t we will calculate it

• speed = ut + 1/2 backward t

• speed = 0 + 1/2 × 0.5 × t

• t = √20 speed

• distance travelled in truck = √20speed

• speed = ut + 1/2

• speed = 0 + 1/2 × 2 × (√20)

• speed = 20 m

• distance travelled in truck = 20 m

Answer 2

$\large\bf\underline\green{GIVEN -:}$

• Rear side of the truck is = 40 kg of mass
• coefficient friction between box and surface is

• = 0.15
• Acceleration = 2m–²

$]\large\bf\underline\purple{We \: have \: to \: find}$

• fall of the truck ignore size of the box = ?

ACCORDING TO THE QUESTION ❓

• Main thing which is given

• box mass = 40 kg

• U = 15

• Speed = 5m

• Acceleration = 2m/s-²

• Force = Mass × Acceleration

SO, NOW

• Force = 40 × 2 = 80

• truck acceleration is

• Force = umg = force

• 0.15 ×40× 10 = 60

• Net force = block

• Force net = 80 - 60 = 20

• Force Net / mass 20/ 40

• Equation of motion of (T) We have to use to calculate

• Speed = 0+1/2 × 5 × T

$\small \bf\underline\green{ \sqrt{20} \: speed }$

• Distance = which truck had travelled .